Kotlin Program to Convert Binary Number to Octal and vice-versa

Example 1: Program to Convert Binary to Octal

In this program, we will first convert binary number to decimal. Then, the decimal number is converted to octal.

              

fun main(args: Array<String>) {
    val binary: Long = 101001
    val octal = convertBinarytoOctal(binary)
    println("$binary in binary = $octal in octal")
}

fun convertBinarytoOctal(binaryNumber: Long): Int {
    var binaryNumber = binaryNumber
    var octalNumber = 0
    var decimalNumber = 0
    var i = 0

    while (binaryNumber.toInt() != 0) {
        decimalNumber += (binaryNumber % 10 * Math.pow(2.0, i.toDouble())).toInt()
        ++i
        binaryNumber /= 10
    }

    i = 1

    while (decimalNumber != 0) {
        octalNumber += decimalNumber % 8 * i
        decimalNumber /= 8
        i *= 10
    }

    return octalNumber
}

            

When you run the program, the output will be:

              

101001 in binary = 51 in octal

            

This conversion takes place as:

              

Binary To Decimal
1 * 25 + 0 * 24 + 1 * 23 + 0 * 22 + 0 * 21 + 1 * 20 = 41

Decimal to Octal
8 | 41
8 | 5 -- 1
8 | 0 -- 5
(51)


            

Example 2: Program to Convert Octal to Binary

In this program, the octal number to decimal to decimal at first. Then, the decimal number is converted to binary number.

              

fun main(args: Array<String>) {
    val octal = 67
    val binary = convertOctalToBinary(octal)
    println("$octal in octal = $binary in binary")
}

fun convertOctalToBinary(octalNumber: Int): Long {
    var octalNumber = octalNumber
    var decimalNumber = 0
    var i = 0
    var binaryNumber: Long = 0

    while (octalNumber != 0) {
        decimalNumber += (octalNumber % 10 * Math.pow(8.0, i.toDouble())).toInt()
        ++i
        octalNumber /= 10
    }

    i = 1

    while (decimalNumber != 0) {
        binaryNumber += (decimalNumber % 2 * i).toLong()
        decimalNumber /= 2
        i *= 10
    }

    return binaryNumber
}

            

When you run the program, the output will be:

              

67 in octal = 110111 in binary

            

This conversion takes place as:

              

Octal To Decimal
6 * 81 + 7 * 80 = 55

Decimal to Binary
2 | 55
2 | 27 -- 1
2 | 13 -- 1
2 | 6  -- 1
2 | 3  -- 0
2 | 1  -- 1
2 | 0  -- 1
(110111)


            

Here’s the equivalent Java code: Java Program to Convert Binary to Octal and vice-versa